(1/6)^x+3=2

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Solution for (1/6)^x+3=2 equation:



(1/6)^x+3=2
We move all terms to the left:
(1/6)^x+3-(2)=0
Domain of the equation: 6)^x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+1/6)^x+3-2=0
We add all the numbers together, and all the variables
(+1/6)^x+1=0
We multiply all the terms by the denominator
(+1+1*6)^x=0
We add all the numbers together, and all the variables
7^x=0
x=0/1
x=0
Równanie nie ma rozwiązania

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